Keamogetswe Maker Modisane
Did you make this yourself? It's wrong
But the answer is x = square root of 5
X is the opposite side of the small angle(alpha), so since we have the adjacent side and the hypotenuse side [cos(alpha) = 2/3], we can use theorem of Pythagoras to find the opposite side, which is x.
But anyway, let's continue so that you can see what's wrong with all this diagram. If cos(beta) = 1/3, then we can find the opposite of beta by using the theorem of Pythagoras. 3squared = 1squared + opposite squared.
9-1 = opposite squared.
sqrt(8) = opposite.
Now, the opposite side of beta is equal to 2 + x
So sqrt(8) = 2 + x
x = sqrt(8) - 2
x = 0.82, tell me if I am wrong
The diagram is wrong. By using theorem of Pythagoras, I can find x by using cos(alpha) = 2/3.
x^2 + 2^2 = 3^2, according to your diagram and theorem of Pythagoras.
Which means x = sqrt(5) = 2.24
Did you make this yourself? It's wrong
But the answer is x = square root of 5
X is the opposite side of the small angle(alpha), so since we have the adjacent side and the hypotenuse side [cos(alpha) = 2/3], we can use theorem of Pythagoras to find the opposite side, which is x.
But anyway, let's continue so that you can see what's wrong with all this diagram. If cos(beta) = 1/3, then we can find the opposite of beta by using the theorem of Pythagoras. 3squared = 1squared + opposite squared.
9-1 = opposite squared.
sqrt(8) = opposite.
Now, the opposite side of beta is equal to 2 + x
So sqrt(8) = 2 + x
x = sqrt(8) - 2
x = 0.82, tell me if I am wrong
The diagram is wrong. By using theorem of Pythagoras, I can find x by using cos(alpha) = 2/3.
x^2 + 2^2 = 3^2, according to your diagram and theorem of Pythagoras.
Which means x = sqrt(5) = 2.24